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0.6x^2=135
We move all terms to the left:
0.6x^2-(135)=0
a = 0.6; b = 0; c = -135;
Δ = b2-4ac
Δ = 02-4·0.6·(-135)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*0.6}=\frac{-18}{1.2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*0.6}=\frac{18}{1.2} =15 $
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